fix(annuaire): Fix case one job an no employer for user

src/users/services/userRegistry.service.ts

@@ -60,19 +60,20 @@ export class UserRegistryService {
     const employersNames: string[] = employersList.map((e) => e.name);
     // For each filter list (job or employer), we'll filter the main user list in order to get only the user that have a job or employer contained in the filters array
     // For this, we une findexIndex method on job/employer name
+
     if (employersList?.length && jobList?.length) {
       return users.filter(
         (user) =>
-          jobNames.findIndex((n) => user.job.name === n) > -1 &&
-          employersNames.findIndex((n) => user.employer.name === n) > -1
+          jobNames.findIndex((n) => user.job?.name === n) > -1 &&
+          employersNames.findIndex((n) => user.employer?.name === n) > -1
       );
     }
 
     if (employersList?.length) {
-      return users.filter((user) => employersNames.findIndex((n) => user.employer.name === n) > -1);
+      return users.filter((user) => employersNames.findIndex((n) => user.employer?.name === n) > -1);
     }
     if (jobList?.length) {
-      return users.filter((user) => jobNames.findIndex((n) => user.job.name === n) > -1);
+      return users.filter((user) => jobNames.findIndex((n) => user.job?.name === n) > -1);
     }
   }